Optimal. Leaf size=148 \[ -\frac{2 \cos (c+d x) (a \sin (c+d x)+a)^{3/2}}{5 a d}+\frac{4 \cos (c+d x) \sqrt{a \sin (c+d x)+a}}{15 d}+\frac{61 a \cos (c+d x)}{15 d \sqrt{a \sin (c+d x)+a}}-\frac{\cot (c+d x) \sqrt{a \sin (c+d x)+a}}{d}-\frac{\sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{a \sin (c+d x)+a}}\right )}{d} \]
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Rubi [A] time = 0.477178, antiderivative size = 148, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 31, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.258, Rules used = {2881, 2759, 2751, 2646, 3044, 2981, 2773, 206} \[ -\frac{2 \cos (c+d x) (a \sin (c+d x)+a)^{3/2}}{5 a d}+\frac{4 \cos (c+d x) \sqrt{a \sin (c+d x)+a}}{15 d}+\frac{61 a \cos (c+d x)}{15 d \sqrt{a \sin (c+d x)+a}}-\frac{\cot (c+d x) \sqrt{a \sin (c+d x)+a}}{d}-\frac{\sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{a \sin (c+d x)+a}}\right )}{d} \]
Antiderivative was successfully verified.
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Rule 2881
Rule 2759
Rule 2751
Rule 2646
Rule 3044
Rule 2981
Rule 2773
Rule 206
Rubi steps
\begin{align*} \int \cos ^2(c+d x) \cot ^2(c+d x) \sqrt{a+a \sin (c+d x)} \, dx &=\int \sin ^2(c+d x) \sqrt{a+a \sin (c+d x)} \, dx+\int \csc ^2(c+d x) \sqrt{a+a \sin (c+d x)} \left (1-2 \sin ^2(c+d x)\right ) \, dx\\ &=-\frac{\cot (c+d x) \sqrt{a+a \sin (c+d x)}}{d}-\frac{2 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{5 a d}+\frac{2 \int \left (\frac{3 a}{2}-a \sin (c+d x)\right ) \sqrt{a+a \sin (c+d x)} \, dx}{5 a}+\frac{\int \csc (c+d x) \left (\frac{a}{2}-\frac{5}{2} a \sin (c+d x)\right ) \sqrt{a+a \sin (c+d x)} \, dx}{a}\\ &=\frac{5 a \cos (c+d x)}{d \sqrt{a+a \sin (c+d x)}}+\frac{4 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{15 d}-\frac{\cot (c+d x) \sqrt{a+a \sin (c+d x)}}{d}-\frac{2 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{5 a d}+\frac{7}{15} \int \sqrt{a+a \sin (c+d x)} \, dx+\frac{1}{2} \int \csc (c+d x) \sqrt{a+a \sin (c+d x)} \, dx\\ &=\frac{61 a \cos (c+d x)}{15 d \sqrt{a+a \sin (c+d x)}}+\frac{4 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{15 d}-\frac{\cot (c+d x) \sqrt{a+a \sin (c+d x)}}{d}-\frac{2 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{5 a d}-\frac{a \operatorname{Subst}\left (\int \frac{1}{a-x^2} \, dx,x,\frac{a \cos (c+d x)}{\sqrt{a+a \sin (c+d x)}}\right )}{d}\\ &=-\frac{\sqrt{a} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (c+d x)}{\sqrt{a+a \sin (c+d x)}}\right )}{d}+\frac{61 a \cos (c+d x)}{15 d \sqrt{a+a \sin (c+d x)}}+\frac{4 \cos (c+d x) \sqrt{a+a \sin (c+d x)}}{15 d}-\frac{\cot (c+d x) \sqrt{a+a \sin (c+d x)}}{d}-\frac{2 \cos (c+d x) (a+a \sin (c+d x))^{3/2}}{5 a d}\\ \end{align*}
Mathematica [A] time = 0.73294, size = 258, normalized size = 1.74 \[ \frac{\csc ^4\left (\frac{1}{2} (c+d x)\right ) \sqrt{a (\sin (c+d x)+1)} \left (155 \sin \left (\frac{1}{2} (c+d x)\right )+87 \sin \left (\frac{3}{2} (c+d x)\right )-5 \sin \left (\frac{5}{2} (c+d x)\right )+3 \sin \left (\frac{7}{2} (c+d x)\right )-155 \cos \left (\frac{1}{2} (c+d x)\right )+87 \cos \left (\frac{3}{2} (c+d x)\right )+5 \cos \left (\frac{5}{2} (c+d x)\right )+3 \cos \left (\frac{7}{2} (c+d x)\right )-30 \sin (c+d x) \log \left (-\sin \left (\frac{1}{2} (c+d x)\right )+\cos \left (\frac{1}{2} (c+d x)\right )+1\right )+30 \sin (c+d x) \log \left (\sin \left (\frac{1}{2} (c+d x)\right )-\cos \left (\frac{1}{2} (c+d x)\right )+1\right )\right )}{30 d \left (\cot \left (\frac{1}{2} (c+d x)\right )+1\right ) \left (\csc \left (\frac{1}{4} (c+d x)\right )-\sec \left (\frac{1}{4} (c+d x)\right )\right ) \left (\csc \left (\frac{1}{4} (c+d x)\right )+\sec \left (\frac{1}{4} (c+d x)\right )\right )} \]
Antiderivative was successfully verified.
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Maple [A] time = 1.055, size = 162, normalized size = 1.1 \begin{align*}{\frac{1+\sin \left ( dx+c \right ) }{15\,\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) d}\sqrt{-a \left ( \sin \left ( dx+c \right ) -1 \right ) } \left ( \sin \left ( dx+c \right ) \left ( 30\,\sqrt{a-a\sin \left ( dx+c \right ) }{a}^{7/2}+20\,{a}^{5/2} \left ( a-a\sin \left ( dx+c \right ) \right ) ^{3/2}-6\,{a}^{3/2} \left ( a-a\sin \left ( dx+c \right ) \right ) ^{5/2}-15\,{\it Artanh} \left ({\frac{\sqrt{a-a\sin \left ( dx+c \right ) }}{\sqrt{a}}} \right ){a}^{4} \right ) -15\,\sqrt{a-a\sin \left ( dx+c \right ) }{a}^{7/2} \right ){a}^{-{\frac{7}{2}}}{\frac{1}{\sqrt{a+a\sin \left ( dx+c \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a \sin \left (d x + c\right ) + a} \cos \left (d x + c\right )^{4} \csc \left (d x + c\right )^{2}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.27564, size = 867, normalized size = 5.86 \begin{align*} \frac{15 \,{\left (\cos \left (d x + c\right )^{2} -{\left (\cos \left (d x + c\right ) + 1\right )} \sin \left (d x + c\right ) - 1\right )} \sqrt{a} \log \left (\frac{a \cos \left (d x + c\right )^{3} - 7 \, a \cos \left (d x + c\right )^{2} - 4 \,{\left (\cos \left (d x + c\right )^{2} +{\left (\cos \left (d x + c\right ) + 3\right )} \sin \left (d x + c\right ) - 2 \, \cos \left (d x + c\right ) - 3\right )} \sqrt{a \sin \left (d x + c\right ) + a} \sqrt{a} - 9 \, a \cos \left (d x + c\right ) +{\left (a \cos \left (d x + c\right )^{2} + 8 \, a \cos \left (d x + c\right ) - a\right )} \sin \left (d x + c\right ) - a}{\cos \left (d x + c\right )^{3} + \cos \left (d x + c\right )^{2} +{\left (\cos \left (d x + c\right )^{2} - 1\right )} \sin \left (d x + c\right ) - \cos \left (d x + c\right ) - 1}\right ) - 4 \,{\left (6 \, \cos \left (d x + c\right )^{4} + 8 \, \cos \left (d x + c\right )^{3} + 40 \, \cos \left (d x + c\right )^{2} +{\left (6 \, \cos \left (d x + c\right )^{3} - 2 \, \cos \left (d x + c\right )^{2} + 38 \, \cos \left (d x + c\right ) + 61\right )} \sin \left (d x + c\right ) - 23 \, \cos \left (d x + c\right ) - 61\right )} \sqrt{a \sin \left (d x + c\right ) + a}}{60 \,{\left (d \cos \left (d x + c\right )^{2} -{\left (d \cos \left (d x + c\right ) + d\right )} \sin \left (d x + c\right ) - d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: TypeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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